Module gopy.search.jumpSearch
Jump search technique also works for ordered lists. It creates a block and tries to find the element in that block. If the item is not in the block, it shifts the entire block. The block size is based on the size of the list. If the size of the list is n then block size will be √n.
After finding a correct block it finds the item using a linear search technique. The jump search lies between linear search and binary search according to its performance.
The complexity of Jump Search Technique
-
Time Complexity: O(√n)
-
Space Complexity: O(1)
Input and Output
Input:
A sorted list of data:
10 13 15 26 28 50 56 88 94 127 159 356 480 567 689 699 780 850 956 995
The search key 356
Output:
Item found at location: 11
Algorithm
jumpSearch(array, size, key)
Input: An sorted array, size of the array and the search key
Output: location of the key (if found), otherwise wrong location.
Begin
blockSize := √size
start := 0
end := blockSize
while array[end] <= key AND end < size do
start := end
end := end + blockSize
if end > size – 1 then
end := size
done
for i := start to end -1 do
if array[i] = key then
return i
done
return invalid location
End
Expand source code
"""
Jump search technique also works for ordered lists. It creates a block and
tries to find the element in that block. If the item is not in the block,
it shifts the entire block. The block size is based on the size of the list.
If the size of the list is n then block size will be √n.
After finding a correct block it finds the item using a linear search technique. The jump
search lies between linear search and binary search according to its performance.
### The complexity of Jump Search Technique
- Time Complexity: O(√n)
- Space Complexity: O(1)
### Input and Output
```
Input:
A sorted list of data:
10 13 15 26 28 50 56 88 94 127 159 356 480 567 689 699 780 850 956 995
The search key 356
Output:
Item found at location: 11
```
### Algorithm
```
jumpSearch(array, size, key)
Input: An sorted array, size of the array and the search key
Output: location of the key (if found), otherwise wrong location.
Begin
blockSize := √size
start := 0
end := blockSize
while array[end] <= key AND end < size do
start := end
end := end + blockSize
if end > size – 1 then
end := size
done
for i := start to end -1 do
if array[i] = key then
return i
done
return invalid location
End
```
"""
import math
def search( x , arr ):
n = len(arr)
# Finding block size to be jumped
step = int(math.sqrt(n))
# Finding the block where element is
# present (if it is present)
prev = 0
while arr[int(min(step, n)-1)] < x:
prev = step
step += int(math.sqrt(n))
if prev >= n:
return "Not Found"
# Doing a linear search for x in
# block beginning with prev.
while arr[int(prev)] < x:
prev += 1
# If we reached next block or end
# of array, element is not present.
if prev == min(step, n):
return "Not Found"
# If element is found
if arr[int(prev)] == x:
return prev
return "Not Found"
Functions
def search(x, arr)
-
Expand source code
def search( x , arr ): n = len(arr) # Finding block size to be jumped step = int(math.sqrt(n)) # Finding the block where element is # present (if it is present) prev = 0 while arr[int(min(step, n)-1)] < x: prev = step step += int(math.sqrt(n)) if prev >= n: return "Not Found" # Doing a linear search for x in # block beginning with prev. while arr[int(prev)] < x: prev += 1 # If we reached next block or end # of array, element is not present. if prev == min(step, n): return "Not Found" # If element is found if arr[int(prev)] == x: return prev return "Not Found"